| Matma / Logarytmy - pomoc |
| Autor | Wiadomość |
| Michal
|
Posted: 4 Kwi 2000 21:17:36 This is a multi-part message in MIME format. ------=_NextPart_000_000A_01BF9E8A.AE977460 Content-Type: text/plain; charset="iso-8859-2" Content-Transfer-Encoding: quoted-printable Witam Grupowiczow! Czy ktos z Was moze mi pomoc? 1) 2log4 (4-x) =3D 4 - log4(-2-x) ___ ___=20 2) log1/2V 2x - log1/2V 2-x =3D - 1/2 3) (log3X)^2 + log3 1/81^3 =3D 0 __ 4) (log2X)^2 + 5log2V x -3/2 =3D 0 Za wyliczenie zadan z gory dziekuje. ------=_NextPart_000_000A_01BF9E8A.AE977460 Content-Type: text/html; charset="iso-8859-2" Content-Transfer-Encoding: quoted-printable <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" <HTML<HEAD <META content=3D"text/html; charset=3Diso-8859-2" = http-equiv=3DContent-Type <META content=3D"MSHTML 5.00.2314.1000" name=3DGENERATOR <STYLE</STYLE </HEAD <BODY <DIV<FONT face=3D"Arial CE" size=3D2Witam Grupowiczow!</FONT</DIV <DIV </DIV <DIV </DIV <DIV<FONT face=3D"Arial CE" size=3D2Czy ktos z Was moze mi = pomoc?</FONT</DIV <DIV </DIV <DIV </DIV <DIV<FONT face=3D"Arial CE"<FONT size=3D21) = 2log</FONT<FONT=20 size=3D14</FONT<FONT size=3D3 (4-x) =3D 4 - <FONT = size=3D2log</FONT<FONT=20 size=3D14</FONT</FONT<FONT size=3D3(-2-x)</FONT</FONT</DIV <DIV<FONT face=3D"Arial CE"=20 size=3D2 &nbs= p; ___ &n= bsp; =20 ___ </FONT</DIV <DIV<FONT face=3D"Arial CE" size=3D22) log<FONT=20 size=3D11/2</FONT<FONT size=3D2V 2x - log<FONT = size=3D11/2<FONT size=3D2V=20 2-x =3D - 1/2</FONT</FONT</FONT</FONT</DIV <DIV<FONT face=3D"Arial CE" size=3D2<FONT size=3D2<FONT = size=3D1<FONT=20 size=3D2</FONT</FONT</FONT</FONT </DIV <DIV<FONT face=3D"Arial CE" size=3D23) (log<FONT = size=3D13</FONT<FONT=20 size=3D2X)^2 +</FONT</FONT <FONT face=3D"Arial CE" = size=3D2log<FONT=20 size=3D13</FONT<FONT size=3D2 1/81^3 =3D 0</FONT</FONT</DIV <DIV<FONT face=3D"Arial CE"=20 size=3D2 &nbs= p;  = ; =20 __</FONT</DIV <DIV<FONT face=3D"Arial CE" size=3D24) (log<FONT = size=3D12</FONT<FONT size=3D2X)^2=20 + 5log</FONT<FONT size=3D12</FONT<FONT size=3D2V x -3/2 =3D=20 0</FONT</FONT</DIV <DIV </DIV <DIV </DIV <DIV<FONT face=3D"Arial CE" size=3D2Za wyliczenie zadan z gory=20 dziekuje.</FONT</DIV <DIV </DIV <DIV<FONT face=3D"Arial CE" size=3D2Pozdrawia Michal - <A=20 <DIV </DIV <DIV </DIV</BODY</HTML ------=_NextPart_000_000A_01BF9E8A.AE977460-- |